MCQ of Coordination Compounds | Multiple Choice Questions of Coordination Compounds
MCQ of Coordination Compounds
Question 1: Which of the following ligands form a chelate?
Answer: B (Oxalate)
Question 2: According to Werner’s theory of coordination compounds
- Primary valency is ionisable
- Secondary valency is ionisable
- Primary and secondary valencies are ionisable
- Neither primary nor secondary valency is ionisable
Answer: A (Primary valency is ionisable)
Question 3: Which of the following rules is not correct regarding IUPAC nomenclature of complex ion?
- Cation is named first and then anion.
- In coordination sphere, the ligands are named alphabetically.
- Positively charged ligands have suffix ‘ate’.
- More than one ligand of a particular type are indicated by using di, tri, tetra etc.
Answer: C ( Positively charged ligands have suffix ‘ate’ )
Question 4: The name of the compound [Co (NH3)5 NO2] Cl2 will be
- pentaamminonitrocobalt (II) chloride
- pentaamminenitrocobalt(III) chloride
Answer: C ( pentaamminenitrocobalt(III) chloride )
Question 5: Identify the statement which is not correct?
- Coordination compound are mainly known for transition metals.
- Coordination number and oxidation state of a metal are same.
- A ligand donates at least one electron pair to the metal atom to form a bond.
- [Co(NH3)4 Cl2]+ is a heteroleptic complex.
Answer: B ( Coordination number and oxidation state of a metal are same.)
Question 6: CrCl3.6H2O exists in different isomeric forms which shows different colours like violet and green. This is due to
- Ionisation isomerism
- Coordination isomerism
- Optical isomerism
- Hydrate isomerism
Answer: D (Hydrate isomerism)
Question 7: Low spin tetrahedral complexes are not formed because
- For tetrahedral complexes, the CFSE is lower than pairing energy
- For tetrahedral complexes, the CFSE is higher than pairing energy
- Electrons do not go to eg in case of tetrahedral complexes
- Tetrahedral complexes are formed by weak ligands only.
Answer: A ( For tetrahedral complexes, the CFSE is lower than pairing energy )
Question 8: [Fe(CN)6]4- and [Fe(H2O)6]2+ show different colours in dilute solution because
- CN¯ is a strong field ligand and H2O is a weak field ligand hence magnitude of CFSE is different
- Both CN¯ and H2O adsorb same wavelength of energy
- Complexes of weak field ligand are generally colourless
- The sizes of CN¯ and H2O are different hence their colours are also different
Answer: A ( CN¯ is a strong field ligand and H2O is a weak field ligand hence magnitude of CFSE is different )
Question 9: Which of the following will form an octahedral complex?
- d4 (low spin)
- d8 (high spin)
- d6 (low spin)
- None of these
Answer: C ( d6 (low spin) )
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Question 10: An example of ambidentate ligand is
Answer: D (Thiacyanato)
Question 11: How many ions are produced from [Co (NH3)6] Cl3 in the solution?
Answer: B (4)
Question 12: The oxidation number of [Co(NH3)(NO2)3] is
Answer: A (+3)
Question 13: The geometry possessed by [Ni(CO)4] is
- Square planar
Answer: A (Tetrahedral)
Question 14: A substance appears coloured because
- It absorbs light at specific wavelength in the visible part and reflects rest of the wavelengths
- Ligands absorb different wavelengths of light which give colour to the complex
- It absorbs white light and shows different colours at different wavelength
- It is diamagnetic in nature
Answer: A ( It absorbs light at specific wavelength in the visible part and reflects rest of the wavelengths )
Question 15:The complex ion which has no d electrons in the central metal atom is
Answer: A ( [MnO4]– )
Question 16: Which of the following is correct?
- Valence bond theory explains the colour of coordination compounds
- [NiCl4]2- is diamagnetic in nature.
- Ambident ligands can show linkage isomerism.
- A bidentate ligand can have four coordination sites.
Answer: C (Ambident ligands can show linkage isomerism)
Question 17: Which of the following is a tridentate ligand?
- EDTA 4-
- (COO)2 2-
Answer: C ( Dien)
Question 18: Which of the following will not show chelation?
Answer: D (SCN‾)
Question 19: The correct structure of Fe(CO)5 is
- Square pyramidal
- Trigonal bipyramidal
Answer: D (Trigonal bipyramidal)
Question 20: State the true statement from the following metal carbonyls
- π back bonding strengthens M—C bond order as well as CO bond order
- π back bonding weakens M—C bond order as well as CO bond order
- π back bonding weakens M—C bond order but strengthens CO bond order
- π back bonding strengthens M—C bond order and weakens CO bond order.
Answer: D ( π back bonding strengthens M—C bond order and weakens CO bond order )
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